(x^2+x)/2=(8*x-7)/3

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Solution for (x^2+x)/2=(8*x-7)/3 equation: 


x in (-oo:+oo)

(x^2+x)/2 = (8*x-7)/3 // - (8*x-7)/3

(x^2+x)/2-((8*x-7)/3) = 0

(x^2+x)/2+(-1*(8*x-7))/3 = 0

(3*(x^2+x))/(2*3)+(-1*2*(8*x-7))/(2*3) = 0

3*(x^2+x)-1*2*(8*x-7) = 0

3*x^2-13*x+14 = 0

3*x^2-13*x+14 = 0

3*x^2-13*x+14 = 0

DELTA = (-13)^2-(3*4*14)

DELTA = 1

DELTA > 0

x = (1^(1/2)+13)/(2*3) or x = (13-1^(1/2))/(2*3)

x = 7/3 or x = 2

(x-2)*(x-7/3) = 0

((x-2)*(x-7/3))/(2*3) = 0

((x-2)*(x-7/3))/(2*3) = 0 // * 2*3

(x-2)*(x-7/3) = 0

( x-2 )

x-2 = 0 // + 2

x = 2

( x-7/3 )

x-7/3 = 0 // + 7/3

x = 7/3

x in { 2, 7/3 }

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